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| Replies Of:hi all
m starting a new thread for QUANTS section.
this is one of the most important section and requires an open outlook to basics.
this thread is meant only for quant section so i request dont post any other section queries
JIMMY |
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| #61 |
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@bhoomi : no yaar u missed the fisheye this time. its not 441... i will give the answers tomorrow. let others try.
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| #62 |
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ok..169 is correct ans,m i???
plz ....
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| #63 |
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@bhoomi2890 can u please explain me the method u have adopted for solving the question????? this answer is also wrong....  .... fine will post teh answers today... 
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| #64 |
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This time im 100% sure the ans is 192...
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| #65 |
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hehe this is again a wrong answer.... this is the answer and solution:::
Let N=123456789101112....
1 to 9>>>> 9 digits
10 to 99>>>180 digits (90 *2)
100 to 359>>>780 digits
Total digits 969
360 to 369 will give 30 digits more and the 1000th digit will be 3(from the no. 370)
So last four digits are 3693.
Numbers 2 and 5 have a special property which says that the for any number N to be divisible by 2^n or 5^n, the last "n" digits have to be divisible by the same.
eg: To check 12345678 to be divisible by 8 or 125...dividing 678 by both will suffice.
For the above problem 3693 mod625 = 568 (625= 5^4)
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| #66 |
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...
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| #67 |
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I have joined this section today... can I put some questions which are known or unknown to me ?
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| #68 |
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@tapan: sure dude...just fire them...
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| #69 |
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In the first 100 even numbers, how many numbers have even number of factors ? 1) 50 2)10 3)90 4) none of these [Give answer in 30 to 60 seconds after you read it, otherwise it is useless]
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| #70 |
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@ all :
CAT2010 notification is out. this is the link....
so anyone who is interested visit this site...
Brochures will be available from 30th August2010.
Best of Luck to all.
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